(5x+2)^2/3=64

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Solution for (5x+2)^2/3=64 equation:


x in (-oo:+oo)

((5*x+2)^2)/3 = 64 // - 64

((5*x+2)^2)/3-64 = 0

((5*x+2)^2)/3+(-64*3)/3 = 0

(5*x+2)^2-64*3 = 0

25*x^2+20*x-188 = 0

25*x^2+20*x-188 = 0

25*x^2+20*x-188 = 0

DELTA = 20^2-(-188*4*25)

DELTA = 19200

DELTA > 0

x = (19200^(1/2)-20)/(2*25) or x = (-19200^(1/2)-20)/(2*25)

x = (80*3^(1/2)-20)/50 or x = (-80*3^(1/2)-20)/50

(x-((-80*3^(1/2)-20)/50))*(x-((80*3^(1/2)-20)/50)) = 0

((x-((-80*3^(1/2)-20)/50))*(x-((80*3^(1/2)-20)/50)))/3 = 0

((x-((-80*3^(1/2)-20)/50))*(x-((80*3^(1/2)-20)/50)))/3 = 0 // * 3

(x-((-80*3^(1/2)-20)/50))*(x-((80*3^(1/2)-20)/50)) = 0

( x-((-80*3^(1/2)-20)/50) )

x-((-80*3^(1/2)-20)/50) = 0 // + (-80*3^(1/2)-20)/50

x = (-80*3^(1/2)-20)/50

( x-((80*3^(1/2)-20)/50) )

x-((80*3^(1/2)-20)/50) = 0 // + (80*3^(1/2)-20)/50

x = (80*3^(1/2)-20)/50

x in { (-80*3^(1/2)-20)/50, (80*3^(1/2)-20)/50 }

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